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How long does a subway train with a maximum allowed speed of 40 m/s and a maximum acceleration of 20 m/s^2 need to travel a distance of 400 m?
To calculate the time it takes for the subway train to travel a distance of 400 m, we can use the equation: distance = initial velocity * time + 0.5 * acceleration * time^2. Given that the initial velocity is 0 m/s, the acceleration is 20 m/s^2, and the distance is 400 m, we can rearrange the equation to solve for time. Plugging in the values, we get: 400 = 0.5 * 20 * time^2. Solving for time, we find that the subway train will take approximately 4 seconds to travel a distance of 400 m. **
How long does a subway train with a maximum allowable speed of 40 m/s and a maximum acceleration of 20 m/s^2 need to travel a distance of 400 m?
To find the time it takes for the subway train to travel a distance of 400 m, we can use the equation of motion: \(v^2 = u^2 + 2as\), where \(v\) is the final velocity, \(u\) is the initial velocity, \(a\) is the acceleration, and \(s\) is the distance. Given that the initial velocity is 0 m/s, the final velocity is 40 m/s, the acceleration is 20 m/s\(^2\), and the distance is 400 m, we can rearrange the equation to solve for time: \(t = \frac{v-u}{a}\). Plugging in the values, we get \(t = \frac{40-0}{20} = 2\) seconds. Therefore, the subway train will take 2 seconds to travel a distance of 400 m. **
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Cybex Agis M-Air3 & Aton Travel System - Grape Juice/Cobblestone---Specs Tables Start---SpecificationsStroller Weight: 21 lbs lbsAge/Weight capacity: Birth to 55 lbsOpen Dimensions: 34 L x 23 W x 39-40 H Folded Dimensions: 14.6 L x 22.4 W x 33 HWhat's Included: Stroller, adapters, car seat & baseWhat's NOT...249,99 $*Shipping: 0,00 $Secure redirect to the provider
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How fast does a 5 m long car travel at a constant speed of 90 km/h?
To find the speed of the car in meters per second, we first convert the speed from kilometers per hour to meters per second. There are 1000 meters in a kilometer and 3600 seconds in an hour, so we can convert 90 km/h to meters per second by multiplying by (1000 m/km)/(3600 s/h) to get 25 m/s. Therefore, the car travels at a constant speed of 25 m/s. **
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How long does a car take to travel 50 m at a speed of 30 km/h?
To calculate the time it takes for the car to travel 50 m at a speed of 30 km/h, we first need to convert the speed from km/h to m/s. 30 km/h is equal to 8.33 m/s. Then, we can use the formula time = distance/speed to find the time it takes for the car to travel 50 m. Plugging in the values, we get time = 50 m / 8.33 m/s = 6 seconds. Therefore, it takes the car 6 seconds to travel 50 m at a speed of 30 km/h. **
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How far does a passenger airplane travel during the takeoff phase if it has a takeoff speed of 290 km/h and an acceleration of 28 m/s²?
To determine the distance traveled during takeoff, we first need to convert the takeoff speed to m/s, which is 80.56 m/s. Using the formula \( v^2 = u^2 + 2as \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the distance traveled, we can calculate the distance traveled during takeoff. Plugging in the values, we get \( 0 = (80.56)^2 + 2(28)s \), which gives us a distance of approximately 115 meters. Therefore, the passenger airplane travels around 115 meters during the takeoff phase. **
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'Others? How long does it take for a signal to travel from one submarine to another, if the speed of sound in water is 1500 m/s and the distance between the two submarines is 75 km?'
The time it takes for a signal to travel from one submarine to another can be calculated using the formula: time = distance / speed. In this case, the distance between the two submarines is 75 km, which is equal to 75,000 meters. The speed of sound in water is 1500 m/s. Plugging these values into the formula, we get: time = 75,000 m / 1500 m/s = 50 seconds. Therefore, it takes 50 seconds for a signal to travel from one submarine to another. **
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How long does a subway train with a maximum allowed speed of 40 m/s and a maximum acceleration of 20 m/s^2 need to travel a distance of 400 m?
To calculate the time it takes for the subway train to travel a distance of 400 m, we can use the equation: distance = initial velocity * time + 0.5 * acceleration * time^2. Given that the initial velocity is 0 m/s, the acceleration is 20 m/s^2, and the distance is 400 m, we can rearrange the equation to solve for time. Plugging in the values, we get: 400 = 0.5 * 20 * time^2. Solving for time, we find that the subway train will take approximately 4 seconds to travel a distance of 400 m. **
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How long does a subway train with a maximum allowable speed of 40 m/s and a maximum acceleration of 20 m/s^2 need to travel a distance of 400 m?
To find the time it takes for the subway train to travel a distance of 400 m, we can use the equation of motion: \(v^2 = u^2 + 2as\), where \(v\) is the final velocity, \(u\) is the initial velocity, \(a\) is the acceleration, and \(s\) is the distance. Given that the initial velocity is 0 m/s, the final velocity is 40 m/s, the acceleration is 20 m/s\(^2\), and the distance is 400 m, we can rearrange the equation to solve for time: \(t = \frac{v-u}{a}\). Plugging in the values, we get \(t = \frac{40-0}{20} = 2\) seconds. Therefore, the subway train will take 2 seconds to travel a distance of 400 m. **
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How fast does a 5 m long car travel at a constant speed of 90 km/h?
To find the speed of the car in meters per second, we first convert the speed from kilometers per hour to meters per second. There are 1000 meters in a kilometer and 3600 seconds in an hour, so we can convert 90 km/h to meters per second by multiplying by (1000 m/km)/(3600 s/h) to get 25 m/s. Therefore, the car travels at a constant speed of 25 m/s. **
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How long does a car take to travel 50 m at a speed of 30 km/h?
To calculate the time it takes for the car to travel 50 m at a speed of 30 km/h, we first need to convert the speed from km/h to m/s. 30 km/h is equal to 8.33 m/s. Then, we can use the formula time = distance/speed to find the time it takes for the car to travel 50 m. Plugging in the values, we get time = 50 m / 8.33 m/s = 6 seconds. Therefore, it takes the car 6 seconds to travel 50 m at a speed of 30 km/h. **
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How far does a passenger airplane travel during the takeoff phase if it has a takeoff speed of 290 km/h and an acceleration of 28 m/s²?
To determine the distance traveled during takeoff, we first need to convert the takeoff speed to m/s, which is 80.56 m/s. Using the formula \( v^2 = u^2 + 2as \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the distance traveled, we can calculate the distance traveled during takeoff. Plugging in the values, we get \( 0 = (80.56)^2 + 2(28)s \), which gives us a distance of approximately 115 meters. Therefore, the passenger airplane travels around 115 meters during the takeoff phase. **
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'Others? How long does it take for a signal to travel from one submarine to another, if the speed of sound in water is 1500 m/s and the distance between the two submarines is 75 km?'
The time it takes for a signal to travel from one submarine to another can be calculated using the formula: time = distance / speed. In this case, the distance between the two submarines is 75 km, which is equal to 75,000 meters. The speed of sound in water is 1500 m/s. Plugging these values into the formula, we get: time = 75,000 m / 1500 m/s = 50 seconds. Therefore, it takes 50 seconds for a signal to travel from one submarine to another. **
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